”" Math Formula?

Saturday, February 23, 2008

JARASANDHA NUMBERS

In our Indian epic Mahabharatha, we come across a demonaic figure named 'JARASANDHA' . He had a boon that if he was split into two parts and thrown apart, the parts would rejoin and return to life. In fact, he was given life by the two halves of his body.
In the field of Mathematics, we have numbers exhibiting the same property as Jarasandha.

Consider a number of the form XC . This may split as two numbers X and C and if these numbers are added and squared we get the same number XC again i.e
XC ----(X+C)^2 = 10^n X +C =XC

ILLUSTRATIONS:
81=(8+1)^2 = (10^1 x8)+1=81
9801=(98+01)^2 =99^2 =9801 =10^2x98+01=9801
3025=(30+25)^2 =55^2= 3025
2025=(20+25)^2 =45^2 =2025
88209=(88+209)^2=297^2 =88209

Can You find such numbers , please give such numbers

2 comments:

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Surya said...

Hi
This is Ponnaluri Surya Prakash(mail id : suryasaran999@gmail.com),
I am a Java Programmer. I found some Jarasandha numbers using Java Program.
Jarasandha Numbers
81
2025
3025
9801
88209
494209
998001
4941729
7441984
24502500
25502500
52881984
60481729
99980001
300814336
493817284

Thanks and Regards
Surya Prakash.